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Spearman

Spearman's Rho — Study Hours Rank vs. Exam Rank

Non-parametric rank correlation for ordinal data. rₛ=.929, Σd², critical t-test for n=8 students.

📊 rₛ = .929, t(6) = 6.15, p < .001
Step-by-step solution

🏅 13 · Spearman Rank Correlation

Study Hours Rank vs Exam Performance Rank
Non-parametric Correlation
Research Question: Is there a monotonic relationship between study hours rank and exam rank (n=8)? Use Spearman when data is ordinal or non-normal.
StudentHoursRank XExam ScoreRank Yd = Rₓ−Rᵧ
A31622−11
B4255111
C5368300
D64745−11
E7571411
F86857−11
G9780611
H10891800
Σ06
Spearman's rₛ
$$r_s = 1 - \frac{6\sum d_i^2}{n(n^2-1)} = 1 - \frac{6\times 6}{8(64-1)} = 1 - \frac{36}{504} = 1 - 0.071 = \mathbf{0.929}$$
Significance test via t
$$t = r_s\sqrt{\frac{n-2}{1-r_s^2}} = 0.929\sqrt{\frac{6}{1-0.863}} = 0.929\times\sqrt{43.8} = 0.929\times 6.62 = \mathbf{6.15},\quad df=6$$
.929
rₛ
6.15
t(6)
<.001
p
Large
Effect
🔴 Strong positive rank correlation — students who study more tend to score higher, rₛ(6) = .929, p < .001.
APA-7
A Spearman rank correlation indicated a strong positive relationship between study hours and exam performance, rₛ(6) = .93, p < .001. Students with more study hours consistently achieved higher exam ranks.
💡 Use Spearman (rₛ) instead of Pearson (r) when: (1) data is ordinal, (2) normality assumption is violated, or (3) outliers are present. The formula 1 − 6Σd²/[n(n²−1)] is exact when there are no ties.