🧠 MindStat

⚠️ Example not found

This example does not exist or may have been moved.

Browse all examples
🔒
Reliability

Cronbach's Alpha — 5-Item Job Satisfaction Scale

Compute Cronbach's α for a 5-item Likert scale. Inter-item covariance matrix, α formula, interpretation.

📊 α = .834 (good reliability)
Step-by-step solution

🔒 8 · Reliability: Cronbach's Alpha

5-Item Job Satisfaction Scale
Reliability
Research Question: Is a 5-item Likert scale measuring job satisfaction internally consistent (n=6 respondents)?
RespondentQ1Q2Q3Q4Q5Sum
14354319
22232211
35455423
43343316
5122128
64544522
2.071.271.272.271.07σ²_T=28.56
Cronbach's Alpha
$$\alpha = \frac{k}{k-1}\left(1 - \frac{\sum s_i^2}{\sigma_T^2}\right)$$ $$\sum s_i^2 = 2.07+1.27+1.27+2.27+1.07 = 7.95$$ $$\alpha = \frac{5}{4}\left(1 - \frac{7.95}{28.56}\right) = 1.25 \times (1 - 0.2783) = 1.25 \times 0.7217 = 0.902$$
0.902
α
5
Items
Excellent
Rating
α = .902 → Excellent internal consistency (George & Mallery: α > .90 = Excellent).
APA-7
The internal consistency of the five-item job satisfaction scale was excellent, α = .90, which exceeds the recommended threshold of .70 (Nunnally, 1978).